# Why is the Logarithm of a negative number undefined?

The Definition of a Logarithm is:

If
Then

Given this definition, since

Then shouldn’t $\ln(-1)=i\pi$? What is wrong with it?

In fact, Ahlfors treatment of complex analysis begins with exponentiation and logarithms. As the other comments point out, once you accept complex values, there is an inherent problem as uniqueness fails: If $t=e^z$, then also $t=e^{z+2n\pi i}$ for any integer $n$, so one has to choose which of these infinitely many values $z+2n\pi i$ will be distinguished as “the” logarithm of $t$.
We can, however, choose the values of logarithm in a way that the resulting function is continuous (in fact, analytic) at the cost of not having it be defined everywhere on $\mathbb C\setminus\{0\}$: We need to remove at least a line from the punctured plane line so that the domain of logarithm does not contain a loop about the origin; continuity imposes this restriction; think of $e^{i\theta}$ for $0\le\theta\le2\pi$, we get a discontinuity once we have completed traveling along the loop. We refer to this choice of domain as a choice of branch. This question further discusses why this is needed.
When one chooses as domain $\mathbb C\setminus\{x+0i\mid x\le 0\}$ with $\log (a+ib)$ being the number $\ln\sqrt{a^2+b^2}+i\arctan(b/a)$, with the arctangent $\theta$ chosen so $-\pi<\theta<\pi$, we call this the Principal branch, usually denoted $\mathrm{Log}(z)$.