Why is the determinant the volume of a parallelepiped in any dimensions?

For n=2, I can visualize that the determinant n×n matrix is the area of the parallelograms by actually calculating the area by coordinates. But how can one easily realize that it is true for any dimensions?


If the column vectors are linearly dependent, both the determinant and the volume are zero.
So assume linear independence.
The determinant remains unchanged when adding multiples of one column to another. This corresponds to a skew translation of the parallelepiped, which does not affect its volume.
By a finite sequence of such operations, you can transform your matrix to diagonal form, where the relation between determinant (=product of diagonal entries) and volume of a “rectangle” (=product of side lengths) is apparent.

Source : Link , Question Author : ahala , Answer Author : Pedro left MSE

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