It seems as if no one has asked this here before, unless I don’t know how to search.
The Gamma function is
\Gamma(\alpha)=\int_0^\infty x^{\alpha-1} e^{-x}\,dx.
Why is
\Gamma\left(\frac{1}{2}\right)=\sqrt{\pi}\text{ ?}
(I’ll post my own answer, but I know there are many ways to show this, so post your own!)
Answer
We only need Euler’s formula:
\Gamma(1-z) \Gamma(z) = \frac{\pi}{\sin \pi z} \Longrightarrow \Gamma^2\left(\frac{1}{2}\right ) = \pi
Attribution
Source : Link , Question Author : Michael Hardy , Answer Author : DonAntonio
