Why is cross product defined in the way that it is?

\mathbf{a}\times \mathbf{b} follows the right hand rule? Why not left hand rule? Why is it a b \sin (x) times the perpendicular vector? Why is \sin (x) used with the vectors but \cos(x) is a scalar product?

So why is cross product defined in the way that it is?
I am mainly interested in the right hand rule defintion too as it is out of reach?

Answer

The cross product originally came from the quaternions, which extend the complex numbers with two other ‘imaginary units’ j and k, that have noncommutative multiplication (i.e. you can have uv \neq vu), but satisfy the relations

i^2 = j^2 = k^2 = ijk = -1

AFAIK, this is the exact form that Hamilton originally conceived them. Presumably the choice that ijk = -1 is simply due to the convenience in writing this formula compactly, although it could have just as easily been an artifact of how he arrived at them.

Vector algebra comes from separating the quaternions into scalars (the real multiples of 1) and vectors (the real linear combinations of i, j, and k). The cross product is literally just the vector component of the ordinary product of two vector quaternions. (the scalar component is the negative of the dot product)

The association of i, j, and k to the unit vectors along the x, y, and z axes is just lexicographic convenience; you’re just associating them in alphabetic order.

Attribution
Source : Link , Question Author : koe , Answer Author : Community

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