I started learning about the Taylor Series in my calculus class, and although I understand the material well enough, I’m not really sure what actual applications there are for the series.

Question: What are the practical applications of the Taylor Series? Whether it’s in a mathematical context, or in real world examples.

**Answer**

One reason is that we can approximate solutions to differential equations this way: For example, if we have

y″

To solve this for y would be difficult, if at all possible. But by representing y as a Taylor series \sum a_nx^n, we can shuffle things around and determine the coefficients of this Taylor series, allowing us to approximate the solution around a desired point.

It’s also useful for determining various infinite sums. For example:

\frac 1 {1-x}=\sum_{n=0}^\infty x^n

\frac 1 {1+x}=\sum_{n=0}^\infty (-1)^nx^n

Integrate:

\ln(1+x)=\sum_{n=0}^\infty \frac{(-1)^nx^{n+1}}{n+1}

Substituting x=1 gives

\ln 2=1-\frac12+\frac13-\frac14+\frac15-\frac16\cdots

There are also applications in physics. If a system under a conservative force (one with an energy function associated with it, like gravity or electrostatic force) is at a stable equilibrium point x_0, then there are no net forces and the energy function is concave upwards (the energy being higher on either side is essentially what makes it stable). In terms of taylor series, the energy function U centred around this point is of the form

U(x)=U_0+k_1(x-x_0)^2+k_2(x-x_0)^3\cdots

Where U_0 is the energy at the minimum x=x_0. For small displacements the high order terms will be very small and can be ignored. So we can approximate this by only looking at the first two terms:

U(x)\approx U_0+k_1(x-x_0)^2\cdots

Now force is the negative derivative of energy (forces send you from high to low energy, proportionally to the energy drop). Applying this, we get that

F=ma=mx”=-2k_1(x-x_0)

Rephrasing in terms of y=x-x_0:

my”=-2k_1y

Which is the equation for a simple harmonic oscillator. Basically, for small displacements around *any* stable equilibrium the system behaves approximately like an oscillating spring, with sinusoidal behaviour. So under certain conditions you can replace a potentially complicated system by another one that’s very well understood and well-studied. You can see this in a pendulum, for example.

As a final point, they’re also useful in determining limits:

\lim_{x\to0}\frac{\sin x-x}{x^3}

\lim_{x\to0}\frac{x-\frac16x^3+\frac 1{120}x^5\cdots-x}{x^3}

\lim_{x\to0}-\frac16+\frac 1{120}x^2\cdots

-\frac16

which otherwise would have been relatively difficult to determine. Because polynomials behave so much more nicely than other functions, we can use taylor series to determine useful information that would be very difficult, if at all possible, to determine directly.

EDIT: I almost forgot to mention the granddaddy:

e^x=1+x+\frac12x^2+\frac16x^3+\frac1{24}x^4\cdots

e^{ix}=1+ix-\frac12x^2-i\frac16x^3+\frac1{24}x^4\cdots

=1-\frac12x^2+\frac1{24}x^4\cdots + ix-i\frac16x^3+i\frac1{120}x^5\cdots

=\cos x+i\sin x

e^{ix}=\cos x+i\sin x

Which is probably the most important equation in complex analysis. This one alone should be motivation enough, the others are really just icing on the cake.

**Attribution***Source : Link , Question Author : Rivasa , Answer Author : Robert Mastragostino*