Prove every odd integer is the difference of two squares

I know that I should use the definition of an odd integer ($2k+1$), but that’s about it.

Thanks in advance!

Answer

Step 1: pick an odd number (like $n=13$ here)

13 squares

Step 2: bend it in “half” (any odd number $n$ can be written as $2k+1$, and $13=2\cdot 6 + 1$)

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Step 3: fill in the blank space

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Step 4: Count squares. (Here, the blue square has area $36=6^2$, while the whole square has area $49=7^2$)

Attribution
Source : Link , Question Author : papercuts , Answer Author : orlandpm

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