The Section on Covering Maps in John Lee’s book “Introduction to Smooth Manifolds” starts like this:

Suppose $\tilde{X}$ and $X$ are topological spaces. A map $\pi : \tilde{X} \to X$ is called a covering map if $\tilde{X}$ is path-connected and locally path connected, … (etc).

I hope this question is not too dumb, but how can a space be path connected, but not locally path connected ?

EDIT: I am aware of spaces that are locally path-connected yet not path-connected, but I cannot come up with a space that is path – connected yet not locally path connected.

**Answer**

One counterexample is a variant on the famous topologist’s sine curve.

Consider the graph of $y = \sin(\pi/x)$ for $0<x<1$, together with a closed arc from the point $(1,0)$ to $(0,0)$:

This space is obviously path-connected, but it is not locally path-connected (or even locally connected) at the point $(0,0)$.

**Attribution***Source : Link , Question Author : harlekin , Answer Author : Jim Belk*