What exactly does $\ll$ mean?

I am familiar that this symbol means much less than.

…but what exactly does “much less than” mean? (Or the corollary, $\gg$)

On Wikipedia, the example they use is that $1\ll 9999999999$

But my thought on that is that $10^{10^{10^{11}}}\ll 10^{10^{10^{11}}}+9999999999$, based on the same logic. But I am confused because the numbers are comparitively.Logically, I am really kinda spent dealing with this issue of mine. Thanks for any input.

**Answer**

The entire point is that it’s **NOT** very clear what “much less than” is. What is “much less than”? In some contexts $1\ll 2$ and in others $ 1\not \ll 2$ but $1 \ll 100000$ and in others, even $1\not\ll 100000$. What precisely makes something “much less than”?

In most contexts, $\ll$ is used in approximation. For example: for $0<x\ll 1$, $(1+x)^n\approx 1+nx$.

So how small does $x$ have to be? Well small enough for the approximation to be “good enough”! What is good enough? It seems like I’m just pushing off the question, and that’s indeed what I’m doing!

The entire point isn’t whether something is “small enough” (big enough), or if the approximation is “good enough”, the point is *control*. Can you *control* the error in a manageable way.

For the example $0<x \ll 1, (1+x)^n \approx 1+nx$. You can make $(1+x)^n$ as close as you’d like to $1+nx$ by making $x$ small enough! I think this is a more rigorous meaning.

$\ll$ is **imprecise** in the sense that you don’t know how “small” something is. But it is **precise** in the sense that it implies that there is some control. There is some way of making the error in the approximation, argument, etc. as small as you’d like, provided that you make $x$ small enough.

**Attribution***Source : Link , Question Author : Community , Answer Author : Cary Bondoc*