Fastest way to check if xy>yxx^y > y^x?

What is the fastest way to check if xy>yx if I were writing a computer program to do that?

The issue is that x and y can be very large.

Answer

If both x and y are positive then you can just check: log(x)x>log(y)y
so if both x and y are greater than e2.7183 then you can just check: x<y

Attribution
Source : Link , Question Author : learner , Answer Author : Henry

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