# Area of a square inside a square created by connecting point-opposite midpoint

Square $ABCD$ has area $1cm^2$ and sides of $1cm$ each.

$H, F, E, G$ are the midpoints of sides $AD, DC, CB, BA$ respectively.

What will the area of the square formed in the middle be?

I know that this problem can be solved by trigonometry by using Area of triangle ($\frac{1}{2}ab\sin{c}$) but,
is there another method or visual proof?

## Answer

By moving small triangles we can make $5$ equal small squares.

Attribution
Source : Link , Question Author : Agile_Eagle , Answer Author : Seyed