A Banach space of (Hamel) dimension κ exists if and only if κℵ0=κ.
How will we prove the converse implication. One sided implication for Hilbert Space is proved in question: Can you equip every vector space with a Hilbert space structure?
If we don’t assume Axiom of Choice, and we have a Banach space with (Hamel Basis B existence given). Will it be true BN equinumerous with B?
Note: BN is not empty as B is specified.
Answer
No, this is not true.
If D is a Dedekind finite set with a Dedekind finite power set, then ℓ1(D) is a Banach space which has a Hamel basis which is also a Schauder basis, and every linear operator from ℓ1(D) to a normed space is continuous.
But if D is Dedekind finite, then |D|ℵ0>|D|. So it suffices to assume that an infinite Dedekind finite set like that exists. Which is of course consistent with the failure of choice.
See also:
Brunner, Norbert “Garnir’s dream spaces with Hamel bases.”
Arch. Math. Logik Grundlag. 26 (1987), no. 3-4, 123–126.
Attribution
Source : Link , Question Author : Sushil , Answer Author : Asaf Karagila